UGC NET Result

NTA UGC NET Result 2019 December: Date, Cut Off, How To Check at ugcnet.nta.nic.in

UGC NET Result 2019 – The National Testing Agency has conducted the UGC NET exam from 2nd to 6th December 2019. UGC NET Result will be declared on 31st December 2019. The result of UGC NET Exam 2019 contains paper-wise marks, overall marks, and percentage obtained by the candidate in the National Eligibility Test for Junior Research Fellow (JRF) and Assistant Professors. Based on the score in UGC NET Result, candidates can know their qualifying status for JRF and Assistant Professor. Candidates can check UGC NET 2019 result from the official website by using their login details. The official website link to check UGC NET result 2019 will be provided on this page. The UGC NET 2019 result will also specify the normalized scores to adjust the difficulty level of the NET paper conducted in different sessions.

Prior to the result of UGC NET 2019, NTA will release UGC NET answer keys to help candidates predict their chances of getting selected for JRFs and Assistant Professors. Also, the UGC NET result for December 2019 will be declared based on the final answer key. In this article, we will provide you with all the necessary details regarding NTA UGC NET Result, Cutoff, Merit List & Normalization Procedure to calculate your scores. Read on to find out everything about NTA UGC NET Result 2019.

CHECK HERE UGC NET CUTOFF 2019 HERE

UGC NET Result 2019 – Important Date

NTA releases UGC NET 2019 result, e-certificate, JRF award letter at login. However the cut off is published in pdf format. Important dates related to the declaration of NET results are as follows.

UGC NET Result December 2019 Important Dates
Date of exam 2 to 6 Dec 2019
Answer key released on 10 Dec 2019
Candidates could challenge answer key until 14 Dec 2019
Final answer key released on 23 Dec 2019
UGC NET result date as per past trends 28 Dec 2019
UGC NET result date as per information bulletin 31 Dec 2019

UGC NET Result 2019: How to check UGC NET 2019 result and download scorecard?

The results for UGC NET 2019 to be announced on NTA NET official website. The test-takers will not receive any personal intimation about the UGC NET Result. The candidates can find the steps and procedures given below to check NTA UGC NET 2019 Result and download scorecard of UGC NET 2019.

Procedure to download UGC NET scorecard/Result

  1. Visit the official website (Official link below)
  2. On the home page, click on the link NTA UGC NET 2019 Result.
  3. On the result page, enter details such as your Application Number/Roll Number and date of birth/password.
  4. Click on Submit.
  5. The NTA UGC NET Result 2019 will be displayed on the screen.
  6. Download the NTA UGC NET Result for further reference.

UGC NET Result 2019 – Click here to check your scorecard and UGC NET 2019 result (Link will be activated on December 31)

Direct Link to Check UGC NET Result

UGC Net Result Available on 31st December 2019
Answer Key CLICK HERE
Official Website CLICK HERE

NTA UGC NET Result: Details mentioned in scorecard

The following details to be mentioned on NTA UGC NET 2019 Result.

  1. Name of the candidate
  2. Registration number of the candidate
  3. Scorecard
  4. Marks obtained in each paper
  5. Total marks obtained
  6. Percentage obtained

NTA UGC NET Result 2019: Merit list and Normalization Procedure

Based on UGC NET result and cutoff, NTA will prepare a merit list to shortlist the eligible candidates. Candidates who secured minimum UGC NET cut off marks will be considered for the merit list. Also, UGC NET Merit List is prepared based on the aggregate scores obtained by the candidates in two papers. The officials will prepare two merit lists namely Category-wise merit list & Subject wise merit list.

UGC NET Result will be prepared with the help of raw and percentile scores. Refer to the formula given below to calculate your UGC NET Normalized percentiles:

UGC net normalized scores

NTA UGC NET 2019 Result: Shortlisting of candidates

  1. Assistant Professor: The NTA officials will shortlist the top 6% names in the merit list to appoint them as Assistant Professor.
  2. Junior Fellowship: Once the Assistant Professor Merit List is released, a separate cut off will be released for Junior Fellowship.

And the normalization procedure to calculate the Junior Fellowship eligibility is given below:

Total Slots in General Category of JRF = (Number of candidates opted for eligibility for Assistant Professor in that subject X Number of slots available under General category) / Total number of general candidates who have opted for JRF and are qualified for eligibility for an Assistant Professor.

UGC NET Qualifying Marks

Minimum marks you need in aggregate of paper 1 and paper 2, in order to be considered for the ‘JRF and Eligibility for Assistant Professor’ and ‘Assistant Professor’ are as follows.

General category 40%
SC, ST, OBC 35%

UGC NET Cut Off

Minimum percentage of marks you need in aggregate of paper 1 and paper 2, in order to be declared as qualified either for the ‘JRF and Eligibility for Assistant Professor’ or ‘Assistant Professor’ are as follows.

UGC NET Cut Off December 2019: Will be published with result.

UGC NET Cut Off June 2019: Click here to view the subject wise and category wise cut offs.

UGC NET December Result 2019

Statistics relevant to the December 2019 exam of UGC NET are as follows.

Number of candidates registered in UGC NET December 2019

Category and Gender Male  Female  Transgender  Total 
General  96084 192040 07 288131
Gen-EWS 37635 29765 05 67405
SC 110402 95003 11 205416
ST 42651 46960 01 89612
OBC NCL 176473 207822 13 384308
Total 463245 571590 37 1034872

Logistics of the UGC NET December 2019 examination

Key aspect Numbers
Regional coordinators 19
City coordinator 200
Observers 600
Centers with live CCTV 700
CCTV cameras 1450
Test practice centers 4800
Students who took mock tests 1,30,000
Jammers used 3100

Marks calculation for UGC NET Result

The process of calculating marks for the result of UGC National Eligibility Test is explained in the following points.

  • NTA calculates marks as per the final answer key of UGC NET 2019.
  • For all the cancelled questions, marked as “ ———–” in the final answer key, all candidates get marks for their UGC NET Result.
  • For every correct answer, candidates get 2 marks.
  • There is no negative marking for incorrect answers.
  • Marks are neither awarded nor deducted for unmarked questions.

Marks in exam = number of correct answers x 2. 

After calculation of raw score, marks are normalized. Normalization procedure implemented for UGC NET result is the same process that applies to all NTA exams.

UGC NET Result 2019: Procedure and Criteria for Declaration of Results

NTA adopts a 6-step process for the purpose of declaration of UGC NET results. These steps are explained here.

Step 1. NTA calculates the total number of candidates who will be declared as qualified in the UGC NET 2019 result. The total slots for eligibility will be equal to 6% of the candidates who have appeared in paper 1 and paper 2 both.

Step 2. Slots will be allocated category wise as per extant reservation policies of the government of India.

Step 3. It is seen how many candidates have obtained the qualifying marks.

Step 4. Now NTA calculates the number of candidates to be declared as qualified for one subject in the UGC NET result December 2019, in one category.

Let subject = S, category = C

Then, the number = Number of candidates belonging to the category ‘C’ who appeared in subject ‘S’ and secured qualifying marks of that category (x) total slots derived for category ‘C’ as per Step 2 (÷) total number of candidates belonging to category ‘C’ over all subjects who secure at least qualifying marks.

This is repeated for all subjects, all categories.

Step 5. If candidate is in the total number calculated in last step, and had also applied for ‘Eligibility for JRF & Eligibility for Assistant Professor both’, then he or she will come under the JRF consideration zone for UGC NET result 2019.

Step 6. Now the number of slots for JRF is calculated.

Now, this number = Number of candidates belonging to the category ‘C’ who qualified for eligibility for assistant professor in subject ‘S’ and opted for JRF (x) total slots for JRF for category ‘C’ (÷) total number of candidates belonging to category ‘C’ over all subjects who have opted for JRF and qualified for eligibility for assistant professor.