Quantitative Aptitude Time and Work Questions for Competitive exams Sep 11 2015



Quantitative Aptitude Topic of the day: Time and Work

If X can do a piece of work in n days, work done by X in 1 day =1/n
If X does 1/n work in a day. X can finish the work in n days.
If X is thrice as good as Y in work,then

  • Ratio of work done by X and Y= 3: 1
  • Ratio of time taken to finish a work by X and Y = 1 : 3

Attempt the following questions to check your level of preparedness for Time and Work questions in competitive exams. You can answer the questions in comments section. Also make sure you checkout September 14th Winner’s Curry Lunch update for solutions to these questions along with the formulae used in VIDEO format by our Subject Expert.

1. 3 men or 5 women can do a work in 6 days. How long will 6 men and 5 women take to finish the work?

1) 2.5 days
2)  2 days
3)  3 days
4) 3.5 days
5) None of these

2. Two pipes A and B can fill a cistern in 37 1/2 minutes and 45 minutes respectively. both pipes are opened. The cistern will be filled in just half an hour, if the pipe B is turned off after:
1) 5 min
2) 9 min
3) 10 min
4) 15 min
5) None of these

3. A pump can fill a tank with water in 2 hours. Because of a leak, it took 7/3 hours to fill the tank. The leak can drain all the water of the tank in:
1) 4 1/3 hrs
2) 7 hrs
3) 8 hrs
4) 14 hrs
5) None of these

4. 4 men can do a piece of work in 10 days. 2 women can do it in 15 days and 5 children can do it in 12 days. In how many days can 8 men, 5 women and 15 children together complete the piece of work?
1) 2 days
2) 3 days
3) 4 days
4) 5 days
5) None of these

5.  Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. the capacity of the tank is:

1) 60 gallons
2) 100 gallons
3) 120 gallons
4) 180 gallons
5) None of these

VIDEO SOLUTIONS FOR SEPTEMBER 10 Mixture and Alligation:

Share these Time and Work questions with everyone you know and check their answers. Also let us know your comments on video solutions.


    • Hi
      In LCM method, we take LCM of all the days that are mentioned in the problem and consider that to be the total units of work. ( Since, LCM would be the number that is divisible by all the numbers. Hence you will be dealing with natural numbers only)

      Say A does a piece of work in 10 days, B does in 5 days and C does in 20 days. In how many days, the whole work will get completed if all of them are working together?

      LCM = (10, 5, 20) = 20
      Total units of work = 20 units
      One day work of A = 20/10 = 2 units
      One day work of B = 20/5 = 4 units
      One day work of C = 20 / 20 = 1 unit

      Total work done in a day = 7 units
      Total days required = (20 / 7) days

      See, you did not have to deal with fractional values