Percentage Questions asked in SSC CGL, SSC CGL What are Percentage Questions, Common Pattern in Percentage questions asked in SSC CGL,Tips to Solve Percentage questions asked in SSC CGLDear MockBankers
The quantitative aptitude section of the SSC CGL exam includes many important topics like ratio and proportion, simple and compound interest, profit and loss, time and work, time and distance, mixture and allegations, algebra, number series, percentage, average etc.
How to solve Percentage Questions for SSC and Banking Exams
Percentages are one of the most important topics of the Quantitative Aptitude section of the SSC CGL examination. This topic always has a high weightage in the exam which means more marks.
But the problem is that it has a lot of calculations and thus consumes a lot of time, which in turn leaves only a fraction of time for other questions in the section.
In the SSC CGL Exam, Percentage Questions are asked in both Tier 1 And Tier 2 exam. In this article, we will discuss tips and tricks to solve Percentage Questions. But before that first, let us know what actually are Percentage based questions.
What are “Percentage” questions
As the name suggests, percentage based questions contain questions related to the calculation of percentage, or even change of percentage.
Percent expresses parttowhole relationship and mathematically it means “out of one hundred” or “per 100”.
To explain it more, we can say that “Parttowhole” is just the mathematical expression for how many parts you have out of the whole thing.
For example, two red balls out of a total of 10 colored balls means 2/10, which mathematically equals 20/100, or 20%.
We generally use percentage to express this parttowhole relationship as a whole number. But sometimes as per the question we can convert it into corresponding fraction or decimal form.
For example in the above case “20% of red balls” means we are talking about 20 out of every 100 colored balls in the lot.
In corresponding fraction we can say it to be 20/100
In corresponding decimal form we can say it to be 0.2
Common Patterns in Percentage Questions asked in SSC, Railways, Banking and Insurance Exams
Pattern 1: What is a% of b ?
This is the most common pattern of percentage based Questions. To solve these type of questions, you need to anslyse the satement and convert it into a mathematical term
What implies that we have to find something, let this be a random variable X
a% of b implies (a/100) * b?
From the above statement it is clear that we have find what the above statement is equal to.
X = (40/100)*70 = 28
One other type of calculation you must be adept is converting fractions, decimals to percents.
 Percent to Decimal: move the decimal point two places to the left.
 For example, 28% = 0.28
 Percent to Fraction: place the percent number in the numerator and 100 in the denominator; simplify.
 For example, 28% = 28/100 = 7/25
 Decimal to Percent: move decimal point two places to the right,
 For example, 0.28 = 28 %
 Fraction to Percent: first convert fraction to decimal, then follow the directions to convert from decimal to percent.
 For example, 7/25 = 28 %
Pattern 2: Single Change in percentage ?
Percent increase or decrease is one of the most common way to represent a change in a given number. Percent increase or decrease is the percentage that the original number increases or decreases.
Formula:
% Increase (or Decrease) = (Change / Original) * 100
Pattern 3: Multiple Change in percentage ?
This type of pattern is widely followed in exams. the difficulty level is comparatively tough.These are called successive percentage change problems.
How to solve Percentage Questions for SSC, Railways, Banking and Insurance Exams
Solving Percent based questions is no rocket science and you can easily solve that by following the tips given below.
Learn all the important formulas.
Formulas for Percentage of Population
If the current population is P and it increases at a rate of R% per annum, then
Population after n years = P*(1 + R/100)^{n}
Formulas for Percentage Increase/Decrease
If the price of an object increases by R% ,
the reduction in consumption so as not to increase the expenditure = [R/(100 + R)] * 100 %
Formulas for Depreciation
If the current value of a car is P and it depreciates at a rate of R% per annum, then
Value of car after n years = P*(1  R/100)^{n}
Recommended Books for Preparation

General points to remember to solve percentage questions
 Firstly remember tables from 1 to 20
 Learn squares up to 30.
 Learn cubes up to 20
 Learn Square root Up to 30
 Learn cube root up to 15
 If there is 1/x fractional increase then you will have 1/(x+1) fractional decrease and vice versa.